(1/25)^2x+3=125^9x+8

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Solution for (1/25)^2x+3=125^9x+8 equation: 



(1/25)^2x+3=125^9x+8

We move all terms to the left:

(1/25)^2x+3-(125^9x+8)=0



Domain of the equation: 25)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/25)^2x-(125^9x+8)+3=0

We get rid of parentheses

(+1/25)^2x-125^9x-8+3=0

We multiply all the terms by the denominator


(+1-125^9x*25)^2x-8*25)^2x+3*25)^2x=0

Wy multiply elements

-5000x^2+(+1-125^9x*25)^2x=0

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